![](https://static.youtibao.com/asksite/comm/h5/images/m_q_title.png)
[单选题]
曲面x2+2y2+3z2=6在点(1,1,1)处的切平面方程为()。
A.x+2y+3z+6=0
B.x+2y+3z-6=0
C.x-2y+3z+6=0
D.x-2y+3z-6=0
查看答案
![](https://static.youtibao.com/asksite/comm/h5/images/solist_ts.png)
A.x+2y+3z+6=0
B.x+2y+3z-6=0
C.x-2y+3z+6=0
D.x-2y+3z-6=0
已知曲面z=4-x2-y2上点P处的切平面平行于平面2x+2y+z-1=0,则点P的坐标为( ).
A.(1,-1,2) B.(-1,1,2) C.(1,1,2) D.(-1,-1,2)