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[主观题]
甲杯中有浓度为20%的盐水1000克,乙杯中有1000克水。把甲杯中盐水的一半倒入乙杯中,混合后再把乙杯
中盐水的一半倒入甲杯中,混合后又把甲杯中的一部分盐水倒入乙杯中,使得甲乙两杯中的盐水同样多。问最后乙杯盐水的浓度为多少?
A.6%
B.7%
C.8%
D.9%
查看答案
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A.6%
B.7%
C.8%
D.9%
A.20% B.20.6% C. 21.2% D.21.4%
A.11.52%
B. 17.28%
C. 28.8%
D. 48%
A.480
B.500
C.520
D.540
A.9%
B.7.5%
C.4.5%
D.3.6%
A. 5.45%
B. 6.15%
C. 7.35%
D. 5.95%
A.3:2
B.1:2
C.2:3
D.3:5
A.3:2
B.1:2
C.2:3
D.3:5
A.2
B.4
C.6
D.8
A.16%
B.18%
C.20%
D.22%